What is the derivative of A/(y^{13)}+Be^y ?

The derivative of A/(y^{13)}+Be^y is -(13A)/(y^{14)}+Be^y

What is the first derivative of A/(y^{13)}+Be^y ?

The first derivative of A/(y^{13)}+Be^y is -(13A)/(y^{14)}+Be^y

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derivative of

\frac{A}{y ^{13}} + B e^{y}

- \frac{13 A}{y ^{14}} + B e^{y}

Solution steps

\frac{d}{d y} (\frac{A}{y ^{13}} + B e^{y})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (\frac{A}{y ^{13}}) + \frac{d}{d y} (B e^{y})

\frac{d}{d y} (\frac{A}{y ^{13}}) = - \frac{13 A}{y ^{14}}

\frac{d}{d y} (B e^{y}) = B e^{y}

= - \frac{13 A}{y ^{14}} + B e^{y}

x = - 2, x = 1, y = 2 x^{2} + 11, y = 0

\int 16 sin^{2} (x) cos^{2} (x) d x

\int_{0}^{5} (7 x - x^{2}) - (2 x) d x

x \to \infty lim (5 + \frac{6}{x})

n = 0 \sum \infty 4^{- n}

What is the derivative of A/(y^{13)}+Be^y ?
The derivative of A/(y^{13)}+Be^y is -(13A)/(y^{14)}+Be^y
What is the first derivative of A/(y^{13)}+Be^y ?
The first derivative of A/(y^{13)}+Be^y is -(13A)/(y^{14)}+Be^y