What is the d/(dy)(ycos(x)+2xe^y) ?

The d/(dy)(ycos(x)+2xe^y) is cos(x)+2xe^y

What is the first d/(dy)(ycos(x)+2xe^y) ?

The first d/(dy)(ycos(x)+2xe^y) is cos(x)+2xe^y

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\frac{d}{d y} (y cos (x) + 2 x e^{y})

cos (x) + 2 x e^{y}

Solution steps

\frac{d}{d y} (y cos (x) + 2 x e^{y})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (y cos (x)) + \frac{d}{d y} (2 x e^{y})

\frac{d}{d y} (y cos (x)) = cos (x)

\frac{d}{d y} (2 x e^{y}) = 2 x e^{y}

= cos (x) + 2 x e^{y}

2 y^{^{''}} - 4 y^{^{'}} + 8 y = 0

y^{^{''}} + 3 y^{^{'}} + 2 y = t

f (x) = 3 (x)^{2} - 2 (x)

\frac{d y}{d x} = 4 - \frac{5 y}{300 - 3 x}

\int \frac{1}{x ^{2}} d x

What is the d/(dy)(ycos(x)+2xe^y) ?
The d/(dy)(ycos(x)+2xe^y) is cos(x)+2xe^y
What is the first d/(dy)(ycos(x)+2xe^y) ?
The first d/(dy)(ycos(x)+2xe^y) is cos(x)+2xe^y