What is the derivative of 21x+x^2 ?

The derivative of 21x+x^2 is 21+2x

What is the first derivative of 21x+x^2 ?

The first derivative of 21x+x^2 is 21+2x

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\frac{d}{d x} (21 x + x^{2})

21 + 2 x

Solution steps

\frac{d}{d x} (21 x + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (21 x) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (21 x) = 21

\frac{d}{d x} (x^{2}) = 2 x

= 21 + 2 x

\frac{d}{d x} (e^{2 x})

\frac{\partial}{\partial x} (6 x + y^{3})

\frac{d}{d x} (x^{3} - 6 x^{2} + 12 x)

\frac{d}{d x} (x^{2} - 2 x + 5)

\int \frac{1}{( a ^{2} + x ^{2} ) ^{\frac{3}{2}}} d x

What is the derivative of 21x+x^2 ?
The derivative of 21x+x^2 is 21+2x
What is the first derivative of 21x+x^2 ?
The first derivative of 21x+x^2 is 21+2x