What is the integral from-2 to 2 of x(x^2+1)^3 ?

The integral from-2 to 2 of x(x^2+1)^3 is 0

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integral from-2 to 2 of x(x^2+1)^3

\int_{- 2}^{2} x (x^{2} + 1)^{3} d x

0

Solution steps

\int_{- 2}^{2} x (x^{2} + 1)^{3} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x (x^{2} + 1)^{3} :

Odd

= 0

\frac{d}{d x} (\frac{( 2 x - 3 ) ^{- 3}}{( 2 - 3 x ) ^{2}})

x \to 0 lim (\frac{x ^{4} + 1}{x ^{2}})

x \to 0 lim (∣ sin (x) ∣^{x})

\int \frac{6 x ^{2} - 2 x - 1}{4 x ^{3} - x} d x

\frac{\partial}{\partial x} (sin (x) \cdot sin (x + y))

What is the integral from-2 to 2 of x(x^2+1)^3 ?
The integral from-2 to 2 of x(x^2+1)^3 is 0