What is the limit as x approaches 0 of ((2x-1))/x ?

The limit as x approaches 0 of ((2x-1))/x is diverges

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limit as x approaches 0 of ((2x-1))/x

x \to 0 lim (\frac{( 2 x - 1 )}{x})

diverges

Solution steps

x \to 0 lim (\frac{2 x - 1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{2 x - 1}{x}) = - \infty

x \to 0 - lim (\frac{2 x - 1}{x}) = \infty

= diverges

f (x) = \frac{5}{x ^{5}} + \frac{3}{x ^{2}}

\int 4 sin^{6} (x) cos (x) d x

h \to \frac{1}{2} lim (\frac{8 h ^{3} - 1}{1 - 2 h})

\frac{8}{tan ^{3} ( \frac{x}{2} )}

\int cos (2 X) d X

What is the limit as x approaches 0 of ((2x-1))/x ?
The limit as x approaches 0 of ((2x-1))/x is diverges