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Popular >

y^'=4y(3-y)

Solution

y^{^{'}} = 4 y (3 - y)

Solution

y = \frac{3}{e ^{- 12 t + c_{1}} + 1}

Solution steps

y^{'} (t) = 4 y (3 - y)

Solve Bernoulli ODE:

y = \frac{3}{e ^{- 12 t + c_{1}} + 1}

y = \frac{3}{e ^{- 12 t + c_{1}} + 1}

Popular Examples

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n = 0 \sum \infty (- \frac{3}{2})^{- 2 n}

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f (x) = \frac{6}{3 x + 1}, (- 1, - 3)

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x \to 2 lim (\frac{( ∣ x - 2 ∣ )}{x})

integral of (3x^2-3x+2)

\int (3 x^{2} - 3 x + 2) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=4y(3-y) ?
The solution for y^'=4y(3-y) is y= 3/(e^{-12t+c_{1)}+1}