What is the solution for y^'+(1+3x^2)y=3+9x^2 ?

The solution for y^'+(1+3x^2)y=3+9x^2 is y=e^{-x^3-x+c_{1}}+3

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y^'+(1+3x^2)y=3+9x^2

y^{^{'}} + (1 + 3 x^{2}) y = 3 + 9 x^{2}

y = e^{- x^{3} - x + c_{1}} + 3

Solution steps

y^{'} (x) + (1 + 3 x^{2}) y = 3 + 9 x^{2}

Solve separable ODE:

y = e^{- x^{3} - x + c_{1}} + 3

y = e^{- x^{3} - x + c_{1}} + 3

\int \frac{1 + 2 t ^{3}}{t} d t

\frac{\partial}{\partial x} (2 e^{2 x})

f (x) = x (x^{3} + 2 x + 3)

y^{^{''}} = a^{2} y

\int \frac{18}{x ( x ^{2} + 4 ) ^{2}} d x

What is the solution for y^'+(1+3x^2)y=3+9x^2 ?
The solution for y^'+(1+3x^2)y=3+9x^2 is y=e^{-x^3-x+c_{1}}+3