What is the tangent of y=sqrt(x)(49.7) ?

The tangent of y=sqrt(x)(49.7) is y=(24.85)/(sqrt(a_{0))}x+(497sqrt(a_{0)})/(20)

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tangent of y=sqrt(x)(49.7)

tangent of

y = x (49.7)

y = \frac{24.85}{a _{0}} x + \frac{497 a _{0}}{20}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0} \cdot 49.7)

Find the slope of

y = x 49.7 : \frac{d y}{d x} = \frac{24.85}{x}

Compute the slope of

y = x 49.7

x = a_{0} : m = \frac{24.85}{a _{0}}

Find the line with slope m=

\frac{24.85}{a _{0}}

and passing through

(a_{0}, a_{0} 49.7) : y = \frac{24.85}{a _{0}} x + \frac{497 a _{0}}{20}

y = \frac{24.85}{a _{0}} x + \frac{497 a _{0}}{20}

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What is the tangent of y=sqrt(x)(49.7) ?
The tangent of y=sqrt(x)(49.7) is y=(24.85)/(sqrt(a_{0))}x+(497sqrt(a_{0)})/(20)