What is the tangent of y=sqrt(7x),(7,7) ?

The tangent of y=sqrt(7x),(7,7) is y= 1/2 x+7/2

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tangent of y=sqrt(7x),(7,7)

tangent of

y = 7 x, (7, 7)

y = \frac{1}{2} x + \frac{7}{2}

Solution steps

Find the slope of

y = 7 x : \frac{d y}{d x} = \frac{7}{2 x}

Compute the slope of

y = 7 x

(7, 7) : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(7, 7) : y = \frac{1}{2} x + \frac{7}{2}

y = \frac{1}{2} x + \frac{7}{2}

\int \frac{x}{3 x ^{2} + 4} d x

f (x) = \frac{x}{2 x - 4}, at x = 5

n = 1 \sum \infty \frac{2}{1 + n ^{2}}

\frac{d}{d x} (- 2 x + 4)

\frac{1}{2 x + 3}

What is the tangent of y=sqrt(7x),(7,7) ?
The tangent of y=sqrt(7x),(7,7) is y= 1/2 x+7/2