What is the derivative of-0.9x^2+1.7x+2.5 ?

The derivative of-0.9x^2+1.7x+2.5 is -1.8x+1.7

What is the first derivative of-0.9x^2+1.7x+2.5 ?

The first derivative of-0.9x^2+1.7x+2.5 is -1.8x+1.7

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\frac{d}{d x} (- 0.9 x^{2} + 1.7 x + 2.5)

- 1.8 x + 1.7

Solution steps

\frac{d}{d x} (- 0.9 x^{2} + 1.7 x + 2.5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.9 x^{2}) + \frac{d}{d x} (1.7 x) + \frac{d}{d x} (2.5)

\frac{d}{d x} (0.9 x^{2}) = 1.8 x

\frac{d}{d x} (1.7 x) = 1.7

\frac{d}{d x} (2.5) = 0

= - 1.8 x + 1.7 + 0

Simplify

= - 1.8 x + 1.7

\int x^{3} arcsin (\frac{1}{x}) d x

\frac{\partial}{\partial x} (y^{3} - x^{2} y)

f (x) = 8 x^{9} - 3 x^{6} + 12 x^{3}

y = 4 x - x^{2}, y = 0

(X - 1) e^{X}

What is the derivative of-0.9x^2+1.7x+2.5 ?
The derivative of-0.9x^2+1.7x+2.5 is -1.8x+1.7
What is the first derivative of-0.9x^2+1.7x+2.5 ?
The first derivative of-0.9x^2+1.7x+2.5 is -1.8x+1.7