What is the integral of-cot(x)csc(x) ?

The integral of-cot(x)csc(x) is csc(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-cot(x)csc(x)

\int - cot (x) csc (x) d x

csc (x) + C

Solution steps

\int - cot (x) csc (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int cot (x) csc (x) d x

Apply u-substitution

: \int - 1 d u

= - \int - 1 d u

Integral of a constant:

\int a d x = a x

= - (- 1) u

Substitute back

u = csc (x)

= - (- 1) csc (x)

Simplify

= csc (x)

Add a constant to the solution

= csc (x) + C

1.4 x^{2} + 0.3 x + 0.25

\int 3 x^{6} d x

\int \frac{x}{x ^{4} + 81} d x

\frac{d}{d x} (\frac{1}{( x ^{2} + 1 ) ^{2}})

\frac{\partial}{\partial u} (ln (u cos (v)))