What is the integral from 0 to pi/2 of sin^2(1) ?

The integral from 0 to pi/2 of sin^2(1) is pi/2 sin^2(1)

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integral from 0 to pi/2 of sin^2(1)

\int_{0}^{\frac{π}{2}} sin^{2} (1) d x

\frac{π}{2} sin^{2} (1)

Decimal Notation

1.11223 \dots

Solution steps

\int_{0}^{\frac{π}{2}} sin^{2} (1) d x

Integral of a constant:

\int a d x = a x

= [sin^{2} (1) x]_{0}^{\frac{π}{2}}

Compute the boundaries:

\frac{π}{2} sin^{2} (1)

= \frac{π}{2} sin^{2} (1)

\frac{d}{d x} (1 - e^{- a x})

\int_{- 1}^{2} y^{3} + 8 d y

\int (1 - t) e^{12 t - 6 t^{2}} d t

y^{^{'}} = y (x y^{2} + 2)

\int x (x + 1) d x

What is the integral from 0 to pi/2 of sin^2(1) ?
The integral from 0 to pi/2 of sin^2(1) is pi/2 sin^2(1)