What is the derivative of x^2+{f}(x) ?

The derivative of x^2+{f}(x) is 2x+derivative of {f}(x)

What is the first derivative of x^2+{f}(x) ?

The first derivative of x^2+{f}(x) is 2x+derivative of {f}(x)

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\frac{d}{d x} (x^{2} + f (x))

2 x + \frac{d}{d x} (f (x))

Solution steps

\frac{d}{d x} (x^{2} + f (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (f (x))

\frac{d}{d x} (x^{2}) = 2 x

= 2 x + \frac{d}{d x} (f (x))

\int sin^{4} (u) d u

y = \frac{a x + b}{c x + d}

\int n e^{- n} d n

f (x) = - 5 ln (sin (x))

\frac{d}{d x} (sin (tan (x)))

What is the derivative of x^2+{f}(x) ?
The derivative of x^2+{f}(x) is 2x+derivative of {f}(x)
What is the first derivative of x^2+{f}(x) ?
The first derivative of x^2+{f}(x) is 2x+derivative of {f}(x)