What is the solution for (1+cos(t))((dy)/(dt))=(1+e^{-y})sin(t) ?

The solution for (1+cos(t))((dy)/(dt))=(1+e^{-y})sin(t) is y=ln((c_{1})/(1+cos(t))-1)

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(1+cos(t))((dy)/(dt))=(1+e^{-y})sin(t)

(1 + cos (t)) (\frac{d y}{d t}) = (1 + e^{- y}) sin (t)

y = ln (\frac{c _{1}}{1 + cos ( t )} - 1)

Solution steps

(1 + cos (t)) (\frac{d y}{d t}) = (1 + e^{- y}) sin (t)

Solve separable ODE:

y = ln (\frac{c _{1}}{1 + cos ( t )} - 1)

y = ln (\frac{c _{1}}{1 + cos ( t )} - 1)

f (x) = (x^{2} + 36) (2 x + 21)

\frac{d y}{d x} = \frac{x}{1 - 4 x ^{2}}

\frac{d ^{3}}{d x ^{3}} ((4 x - 3)^{\frac{1}{2}})

\frac{\partial}{\partial y} (2 x + y^{3})

x \to 1 lim (\frac{∣ x - 8 ∣}{x - 8})

What is the solution for (1+cos(t))((dy)/(dt))=(1+e^{-y})sin(t) ?
The solution for (1+cos(t))((dy)/(dt))=(1+e^{-y})sin(t) is y=ln((c_{1})/(1+cos(t))-1)