What is derivative of y(θ)=4sin(θ)-3cos(θ) ?

The answer to derivative of y(θ)=4sin(θ)-3cos(θ) is (dy}{dx}=\frac{4cos(x)+3sin(x)-y)/x

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derivative of y(θ)=4sin(θ)-3cos(θ)

derivative of

y = 4 sin (x) - 3 cos (x)

\frac{d y}{d x} = \frac{4 cos ( x ) + 3 sin ( x ) - y}{x}

Solution steps

y x = 4 sin (x) - 3 cos (x)

Treat

y

y (x)

Differentiate both sides:

x \frac{d y}{d x} + y = 4 cos (x) + 3 sin (x)

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{4 cos ( x ) + 3 sin ( x ) - y}{x}

\frac{d y}{d x} = \frac{4 cos ( x ) + 3 sin ( x ) - y}{x}

\int \frac{x ^{2}}{( 1 - x ^{2} ) ^{\frac{1}{2}}} d x

\int 15 e^{- 5 t} d t

\int 4 sec^{2} (4 x) tan (4 x) d x

\int 10 sin (x) d x

\frac{d y}{d x} = \frac{( x - 1 ) ( y + 3 )}{( x + 4 ) ( y - 2 )}

What is derivative of y(θ)=4sin(θ)-3cos(θ) ?
The answer to derivative of y(θ)=4sin(θ)-3cos(θ) is (dy}{dx}=\frac{4cos(x)+3sin(x)-y)/x