What is the derivative of y=(x^2-4x+3)/(x^2) ?

The derivative of y=(x^2-4x+3)/(x^2) is (2(2x-3))/(x^3)

What is the first derivative of y=(x^2-4x+3)/(x^2) ?

The first derivative of y=(x^2-4x+3)/(x^2) is (2(2x-3))/(x^3)

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derivative of

y = \frac{x ^{2} - 4 x + 3}{x ^{2}}

\frac{2 ( 2 x - 3 )}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 4 x + 3}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 4 x + 3 ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( x ^{2} - 4 x + 3 )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (x^{2} - 4 x + 3) = 2 x - 4

\frac{d}{d x} (x^{2}) = 2 x

= \frac{( 2 x - 4 ) x ^{2} - 2 x ( x ^{2} - 4 x + 3 )}{( x ^{2} ) ^{2}}

Simplify

\frac{( 2 x - 4 ) x ^{2} - 2 x ( x ^{2} - 4 x + 3 )}{( x ^{2} ) ^{2}} : \frac{2 ( 2 x - 3 )}{x ^{3}}

= \frac{2 ( 2 x - 3 )}{x ^{3}}

\int_{1}^{2} \frac{1}{2 x - 1} d x

\int 27 - x^{2} d x

x \to \frac{π}{2} lim (e^{t a n (x)})

y = \frac{4 x}{x ^{2} + 1}

\int 38 d x

What is the derivative of y=(x^2-4x+3)/(x^2) ?
The derivative of y=(x^2-4x+3)/(x^2) is (2(2x-3))/(x^3)
What is the first derivative of y=(x^2-4x+3)/(x^2) ?
The first derivative of y=(x^2-4x+3)/(x^2) is (2(2x-3))/(x^3)