What is the limit as x approaches 1 of (x-1)^{(x+4)} ?

The limit as x approaches 1 of (x-1)^{(x+4)} is 0

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limit as x approaches 1 of (x-1)^{(x+4)}

x \to 1 lim ((x - 1)^{(x + 4)})

0

Solution steps

x \to 1 lim ((x - 1)^{x + 4})

Plug in the value

x = 1

= (1 - 1)^{1 + 4}

Simplify

= 0

(2 x y^{2} - 6) d x + (2 x^{2} y + 7) d y = 0

\int (x + 1)^{2} d x

x^{3} y^{2} = x y^{3} + 6

\int \frac{1}{x ^{2} x ^{2} - 15} d x

y = x^{2}, y = - x + 2

What is the limit as x approaches 1 of (x-1)^{(x+4)} ?
The limit as x approaches 1 of (x-1)^{(x+4)} is 0