What is the solution for y^{''}+y-2*cos(x)=0 ?

The solution for y^{''}+y-2*cos(x)=0 is y=c_{1}cos(x)+c_{2}sin(x)+xsin(x)

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y^{''}+y-2*cos(x)=0

y^{^{''}} + y - 2 \cdot cos (x) = 0

y = c_{1} cos (x) + c_{2} sin (x) + x sin (x)

Solution steps

y^{''} (x) + y - 2 \cdot cos (x) = 0

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + x sin (x)

y = c_{1} cos (x) + c_{2} sin (x) + x sin (x)

ln (t^{2} - 2 t + 10)

\frac{1}{x}, x^{2}, [1, e]

\int \frac{5 x}{( x - 1 ) ^{3}} d x

\frac{\partial}{\partial x} (y^{5} sin (4 x))

y (x + 7) + y^{^{'}} = 0, y (- 14) = 1

What is the solution for y^{''}+y-2*cos(x)=0 ?
The solution for y^{''}+y-2*cos(x)=0 is y=c_{1}cos(x)+c_{2}sin(x)+xsin(x)