What is the solution for (dy)/(dx)= 1/(x(ln(2))) ?

The solution for (dy)/(dx)= 1/(x(ln(2))) is y=(ln(x))/(ln(2))+c_{1}

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(dy)/(dx)= 1/(x(ln(2)))

\frac{d y}{d x} = \frac{1}{x ( ln ( 2 ) )}

y = \frac{ln ( x )}{ln ( 2 )} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{1}{x ( ln ( 2 ) )}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = \frac{1}{x ( ln ( 2 ) )}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{1}{x ln ( 2 )} d x

\int \frac{1}{x ln ( 2 )} d x = \frac{1}{ln ( 2 )} ln (x) + c_{1}

y = \frac{1}{ln ( 2 )} ln (x) + c_{1}

Simplify

y = \frac{ln ( x )}{ln ( 2 )} + c_{1}

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What is the solution for (dy)/(dx)= 1/(x(ln(2))) ?
The solution for (dy)/(dx)= 1/(x(ln(2))) is y=(ln(x))/(ln(2))+c_{1}