What is the sum from n=1 to infinity of (5n)/(2n+5) ?

The sum from n=1 to infinity of (5n)/(2n+5) is diverges

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sum from n=1 to infinity of (5n)/(2n+5)

n = 1 \sum \infty \frac{5 n}{2 n + 5}

diverges

Solution steps

n = 1 \sum \infty \frac{5 n}{2 n + 5}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 1 \sum \infty \frac{n}{2 n + 5}

Apply Series Divergence Test:

diverges

= 5 diverges

= diverges

\frac{d}{d x} (\frac{25 - x ^{2}}{4 x})

\frac{\partial}{\partial x} (- 12 x y)

x y^{^{'}} - 3 y = 0

y (\frac{x - y}{x + y})

\int \frac{1}{16 x ^{2} + 2} d x

What is the sum from n=1 to infinity of (5n)/(2n+5) ?
The sum from n=1 to infinity of (5n)/(2n+5) is diverges