What is (\partial)/(\partial r)(rsin(t)sin(x)) ?

The answer to (\partial)/(\partial r)(rsin(t)sin(x)) is sin(t)sin(x)

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(\partial)/(\partial r)(rsin(t)sin(x))

\frac{\partial}{\partial r} (r sin (t) sin (x))

sin (t) sin (x)

Solution steps

\frac{\partial}{\partial r} (r sin (t) sin (x))

Treat

t, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (t) sin (x) \frac{\partial}{\partial r} (r)

Apply the common derivative:

\frac{\partial}{\partial r} (r) = 1

= sin (t) sin (x) \cdot 1

Simplify

= sin (t) sin (x)

\int_{0}^{1} \frac{17}{4 y - 1} d y

\frac{6}{s} + 8 a \cdot \frac{s}{s ^{2} + 16}

\frac{d}{d x} (4 x^{4} + \frac{1}{3} x^{3} + x + 1)

h

What is (\partial)/(\partial r)(rsin(t)sin(x)) ?
The answer to (\partial)/(\partial r)(rsin(t)sin(x)) is sin(t)sin(x)