What is the tangent of y=(7x)/(x-1),(2,14) ?

The tangent of y=(7x)/(x-1),(2,14) is y=-7x+28

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tangent of y=(7x)/(x-1),(2,14)

tangent of

y = \frac{7 x}{x - 1}, (2, 14)

y = - 7 x + 28

Solution steps

Find the slope of

y = \frac{7 x}{x - 1} : \frac{d y}{d x} = - \frac{7}{( x - 1 ) ^{2}}

Compute the slope of

y = \frac{7 x}{x - 1}

(2, 14) : m = - 7

Find the line with slope m=

- 7

and passing through

(2, 14) : y = - 7 x + 28

y = - 7 x + 28

\frac{\partial}{\partial x} ((x + 2)^{2} \cdot (1 + \frac{1}{y})^{3})

y = x^{2} + 11

\frac{\partial}{\partial z} (x - z)

\frac{\partial}{\partial x} (x^{5} y^{- \frac{1}{2}})

\frac{\partial}{\partial x} (\frac{3 t}{2 s})

What is the tangent of y=(7x)/(x-1),(2,14) ?
The tangent of y=(7x)/(x-1),(2,14) is y=-7x+28