What is the tangent of y=-2sin(x),\at x= 3/4 pi ?

The tangent of y=-2sin(x),\at x= 3/4 pi is y=sqrt(2)x-sqrt(2)-(3pi)/(2sqrt(2))

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tangent of y=-2sin(x),\at x= 3/4 pi

tangent of

y = - 2 sin (x), at x = \frac{3}{4} π

y = 2 x - 2 - \frac{3 π}{2 2}

Solution steps

Find the tangent point:

(\frac{3}{4} π, - 2)

Find the slope of

y = - 2 sin (x) : \frac{d y}{d x} = - 2 cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(\frac{3}{4} π, - 2) : y = 2 x - 2 - \frac{3 π}{2 2}

y = 2 x - 2 - \frac{3 π}{2 2}

\frac{d}{d x} (\frac{cos ( x )}{1 + cos ( x )})

n = 0 \sum \infty \frac{4 n}{- 4 n + 7}

3 x - 1, x^{2} + 1, 1, 2

f (x) = 30 + 10 e^{- 0.05 x}

cos^{2} (t)

What is the tangent of y=-2sin(x),\at x= 3/4 pi ?
The tangent of y=-2sin(x),\at x= 3/4 pi is y=sqrt(2)x-sqrt(2)-(3pi)/(2sqrt(2))