What is the integral of sin^3(x) ?

The integral of sin^3(x) is -cos(x)+(cos^3(x))/3+C

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integral of sin^3(x)

\int sin^{3} (x) d x

- cos (x) + \frac{cos ^{3} ( x )}{3} + C

Solution steps

\int sin^{3} (x) d x

Rewrite using trig identities

= \int (1 - cos^{2} (x)) sin (x) d x

Apply u-substitution

: \int - 1 + u^{2} d u

= \int - 1 + u^{2} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 1 d u + \int u^{2} d u

\int 1 d u = u

\int u^{2} d u = \frac{u ^{3}}{3}

= - u + \frac{u ^{3}}{3}

Substitute back

u = cos (x)

= - cos (x) + \frac{cos ^{3} ( x )}{3}

Add a constant to the solution

= - cos (x) + \frac{cos ^{3} ( x )}{3} + C

x \to - 2 lim (x (x - 1))

\frac{2000 x}{4 x + 75}

\int y + 1 d y

9 cos (x), 7 sin (x), 0, π

\frac{d}{d x} (x^{2} e^{x} - 2 x e^{x} + 9 e^{x})

What is the integral of sin^3(x) ?
The integral of sin^3(x) is -cos(x)+(cos^3(x))/3+C