What is the tangent of y= 4/(sqrt(x)) ?

The tangent of y= 4/(sqrt(x)) is y=-2/(a_{0)^{3/2}}x+6/(sqrt(a_{0))}

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tangent of y= 4/(sqrt(x))

tangent of

y = \frac{4}{x}

y = - \frac{2}{a _{0}^{\frac{3}{2}}} x + \frac{6}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{4}{a _{0}})

Find the slope of

y = \frac{4}{x} : \frac{d y}{d x} = - \frac{2}{x ^{\frac{3}{2}}}

Compute the slope of

y = \frac{4}{x}

x = a_{0} : m = - \frac{2}{a _{0}^{\frac{3}{2}}}

Find the line with slope m=

- \frac{2}{a _{0}^{\frac{3}{2}}}

and passing through

(a_{0}, \frac{4}{a _{0}}) : y = - \frac{2}{a _{0}^{\frac{3}{2}}} x + \frac{6}{a _{0}}

y = - \frac{2}{a _{0}^{\frac{3}{2}}} x + \frac{6}{a _{0}}

x \to 2 π lim (f (x))

x \to - 4 lim (+ (x^{2} + 10 x + 8))

\frac{d}{d y} (1 - e^{y})

\int (10 - (14 - 2 16 - 2 x)) d x

\frac{d}{d x} (\frac{4 - 4 x - x ^{2}}{x ^{2} - 6})

What is the tangent of y= 4/(sqrt(x)) ?
The tangent of y= 4/(sqrt(x)) is y=-2/(a_{0)^{3/2}}x+6/(sqrt(a_{0))}