What is the tangent of f(x)= 3/x ,\at x=-2 ?

The tangent of f(x)= 3/x ,\at x=-2 is y=-3/4 x-3

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tangent of f(x)= 3/x ,\at x=-2

tangent of

f (x) = \frac{3}{x}, at x = - 2

y = - \frac{3}{4} x - 3

Solution steps

Find the tangent point:

(- 2, - \frac{3}{2})

Find the slope of

f (x) = \frac{3}{x} : \frac{df ( x )}{d x} = - \frac{3}{x ^{2}}

Compute the slope of

f (x) = \frac{3}{x}

x = - 2 : m = - \frac{3}{4}

Find the line with slope m=

- \frac{3}{4}

and passing through

(- 2, - \frac{3}{2}) : y = - \frac{3}{4} x - 3

y = - \frac{3}{4} x - 3

k = 1 \sum \infty \frac{x ^{k}}{k 3 ^{k}}

\int (x^{2} - 5)^{2} 2 x d x

7 x y^{^{'}} = 2 x e^{x} - 7 y + 6 x^{2}

\frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (7 x (sin (3 x^{2} y)))

What is the tangent of f(x)= 3/x ,\at x=-2 ?
The tangent of f(x)= 3/x ,\at x=-2 is y=-3/4 x-3