What is the derivative of (x^2+1)/(x^3-1) ?

The derivative of (x^2+1)/(x^3-1) is (-x^4-3x^2-2x)/((x^3-1)^2)

What is the first derivative of (x^2+1)/(x^3-1) ?

The first derivative of (x^2+1)/(x^3-1) is (-x^4-3x^2-2x)/((x^3-1)^2)

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derivative of

\frac{x ^{2} + 1}{x ^{3} - 1}

\frac{- x ^{4} - 3 x ^{2} - 2 x}{( x ^{3} - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 1}{x ^{3} - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} + 1 ) ( x ^{3} - 1 ) - \frac{d}{d x} ( x ^{3} - 1 ) ( x ^{2} + 1 )}{( x ^{3} - 1 ) ^{2}}

\frac{d}{d x} (x^{2} + 1) = 2 x

\frac{d}{d x} (x^{3} - 1) = 3 x^{2}

= \frac{2 x ( x ^{3} - 1 ) - 3 x ^{2} ( x ^{2} + 1 )}{( x ^{3} - 1 ) ^{2}}

Expand

2 x (x^{3} - 1) - 3 x^{2} (x^{2} + 1) : - x^{4} - 3 x^{2} - 2 x

= \frac{- x ^{4} - 3 x ^{2} - 2 x}{( x ^{3} - 1 ) ^{2}}

x^{2} y^{^{''}} - x y^{^{'}} + y = 2 x

\frac{d}{d x} (x + x + 3)

\int_{3}^{7} x x - 3 d x

\frac{1}{2} ln (\frac{1 + x}{1 - x})

\int 1. 8^{0.045 x} - 1 d x

What is the derivative of (x^2+1)/(x^3-1) ?
The derivative of (x^2+1)/(x^3-1) is (-x^4-3x^2-2x)/((x^3-1)^2)
What is the first derivative of (x^2+1)/(x^3-1) ?
The first derivative of (x^2+1)/(x^3-1) is (-x^4-3x^2-2x)/((x^3-1)^2)