What is derivative of f(x)=2t^{-1/4} ?

The answer to derivative of f(x)=2t^{-1/4} is (dt)/(dx)=0

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derivative of f(x)=2t^{-1/4}

derivative of

f (x) = 2 t^{- \frac{1}{4}}

\frac{d t}{d x} = 0

Solution steps

f (x) = 2 t^{- \frac{1}{4}}

Treat

t

t (x)

Differentiate both sides:

0 = - \frac{\frac{d t}{d x}}{2 t ^{\frac{5}{4}}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

sin (5 ln (x))

f (x) = \frac{2 x}{x ^{2} + 1}, at x = 0

x \to \infty lim (- 7 x)

\int \frac{1}{x ^{2} + 14 x} d x

\int e^{2 u} d u

What is derivative of f(x)=2t^{-1/4} ?
The answer to derivative of f(x)=2t^{-1/4} is (dt)/(dx)=0