What is the solution for y^'-2/x y=(y^3)/(x^3),y(1)=1 ?

The solution for y^'-2/x y=(y^3)/(x^3),y(1)=1 is y=(x^2)/(sqrt(-x^2+2))

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y^'-2/x y=(y^3)/(x^3),y(1)=1

y^{^{'}} - \frac{2}{x} y = \frac{y ^{3}}{x ^{3}}, y (1) = 1

y = \frac{x ^{2}}{- x ^{2} + 2}

Solution steps

y^{'} (x) - \frac{2}{x} y = \frac{y ^{3}}{x ^{3}}

Solve Bernoulli ODE:

y = \frac{x ^{2}}{- x ^{2} + 2}

y = \frac{x ^{2}}{- x ^{2} + 2}

- \frac{2}{5} x^{2}, at x = - 1

- \frac{cos ( \frac{1}{x} )}{x ^{2}}

y = e^{x}, (0, 1)

\frac{6}{3 x + 1}

\frac{d}{d x} (\frac{3 x ^{5} + 9}{x ^{3}})

What is the solution for y^'-2/x y=(y^3)/(x^3),y(1)=1 ?
The solution for y^'-2/x y=(y^3)/(x^3),y(1)=1 is y=(x^2)/(sqrt(-x^2+2))