What is the integral of (4/(sqrt(1-x^2))) ?

The integral of (4/(sqrt(1-x^2))) is 4arcsin(x)+C

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integral of (4/(sqrt(1-x^2)))

\int (\frac{4}{1 - x ^{2}}) d x

4 arcsin (x) + C

Solution steps

\int \frac{4}{1 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= 4 arcsin (x)

Add a constant to the solution

= 4 arcsin (x) + C

\frac{2}{s ^{3} ( s ^{2} + 5 )}

\int_{0}^{1} t^{3} (4 + t^{4})^{3} d t

2 y^{^{''}} + 2 y + y = 0

\int_{1}^{5} 5 x - \frac{5}{x} d x

\int \frac{x ^{5}}{( 2 - x ^{6} ) ^{2}} d x

What is the integral of (4/(sqrt(1-x^2))) ?
The integral of (4/(sqrt(1-x^2))) is 4arcsin(x)+C