What is derivative of y(θ)=2-θ^5sin(θ) ?

The answer to derivative of y(θ)=2-θ^5sin(θ) is (dy}{dx}=\frac{-x^5cos(x)-5x^4sin(x)-y)/x

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derivative of y(θ)=2-θ^5sin(θ)

derivative of

y = 2 - x^{5} sin (x)

\frac{d y}{d x} = \frac{- x ^{5} cos ( x ) - 5 x ^{4} sin ( x ) - y}{x}

Solution steps

y x = 2 - x^{5} sin (x)

Treat

y

y (x)

Differentiate both sides:

x \frac{d y}{d x} + y = - x^{5} cos (x) - 5 x^{4} sin (x)

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- x ^{5} cos ( x ) - 5 x ^{4} sin ( x ) - y}{x}

\frac{d y}{d x} = \frac{- x ^{5} cos ( x ) - 5 x ^{4} sin ( x ) - y}{x}

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\int \frac{x ^{2}}{e ^{x^{3}}} d x

What is derivative of y(θ)=2-θ^5sin(θ) ?
The answer to derivative of y(θ)=2-θ^5sin(θ) is (dy}{dx}=\frac{-x^5cos(x)-5x^4sin(x)-y)/x