What is the integral from 0 to 2 of xe^x ?

The integral from 0 to 2 of xe^x is e^2+1

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integral from 0 to 2 of xe^x

\int_{0}^{2} x e^{x} d x

e^{2} + 1

Decimal Notation

8.38905 \dots

Solution steps

\int_{0}^{2} x e^{x} d x

Apply Integration By Parts

: [e^{x} x - \int e^{x} d x]_{0}^{2}

= [e^{x} x - \int e^{x} d x]_{0}^{2}

\int e^{x} d x = e^{x}

= [e^{x} x - e^{x}]_{0}^{2}

Compute the boundaries:

e^{2} + 1

= e^{2} + 1

\int \frac{49 x ^{2} - 100}{x ^{3}} d x

y = tan (x)

\frac{d}{d x} (cos (x - y))

\frac{\partial}{\partial y} (6 y + \frac{1}{x} - \frac{x}{y ^{2}})

\frac{d}{d x} (\frac{x}{x + 8})

What is the integral from 0 to 2 of xe^x ?
The integral from 0 to 2 of xe^x is e^2+1