What is the first d/(dt)(5ln(t)) ?

The first d/(dt)(5ln(t)) is 5/t

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d/(dt)(5ln(t))

\frac{d}{d t} (5 ln (t))

\frac{5}{t}

Solution steps

\frac{d}{d t} (5 ln (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d t} (ln (t))

Apply the common derivative:

\frac{d}{d t} (ln (t)) = \frac{1}{t}

= 5 \cdot \frac{1}{t}

Simplify

5 \cdot \frac{1}{t} : \frac{5}{t}

= \frac{5}{t}

n = 0 \sum \infty (\frac{5}{16})^{n}

\frac{d}{d u} (e^{- u})

x \to 2 lim (x^{2} + 2 x + 4)

x \to 1 lim (\frac{x}{1 - x})