What is (\partial)/(\partial y)(xe^{y-z}) ?

The answer to (\partial)/(\partial y)(xe^{y-z}) is e^{y-z}x

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(\partial)/(\partial y)(xe^{y-z})

\frac{\partial}{\partial y} (x e^{y - z})

e^{y - z} x

Solution steps

\frac{\partial}{\partial y} (x e^{y - z})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial y} (e^{y - z})

Apply the chain rule:

e^{y - z} \frac{\partial}{\partial y} (y - z)

= e^{y - z} \frac{\partial}{\partial y} (y - z)

\frac{\partial}{\partial y} (y - z) = 1

= x e^{y - z} \cdot 1

Simplify

= e^{y - z} x

\frac{d}{d x} (- e^{- x} - e^{- x} x)

\frac{d y}{d x} = 0.0017 y (900 - y)

cos (e^{- 2 θ^{5}})

\frac{\partial}{\partial x} (arctan (x + 6 y))

x \to \infty lim (ln (- 1))

What is (\partial)/(\partial y)(xe^{y-z}) ?
The answer to (\partial)/(\partial y)(xe^{y-z}) is e^{y-z}x