What is the derivative of y=ln(7x^2+3y^2) ?

The derivative of y=ln(7x^2+3y^2) is (14x)/(7x^2+3y^2)

What is the first derivative of y=ln(7x^2+3y^2) ?

The first derivative of y=ln(7x^2+3y^2) is (14x)/(7x^2+3y^2)

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derivative of

y = ln (7 x^{2} + 3 y^{2})

\frac{14 x}{7 x ^{2} + 3 y ^{2}}

Solution steps

\frac{d}{d x} (ln (7 x^{2} + 3 y^{2}))

Treat

y

as a constant

Apply the chain rule:

\frac{1}{7 x ^{2} + 3 y ^{2}} \frac{d}{d x} (7 x^{2} + 3 y^{2})

= \frac{1}{7 x ^{2} + 3 y ^{2}} \frac{d}{d x} (7 x^{2} + 3 y^{2})

\frac{d}{d x} (7 x^{2} + 3 y^{2}) = 14 x

= \frac{1}{7 x ^{2} + 3 y ^{2}} \cdot 14 x

Simplify

\frac{1}{7 x ^{2} + 3 y ^{2}} \cdot 14 x : \frac{14 x}{7 x ^{2} + 3 y ^{2}}

= \frac{14 x}{7 x ^{2} + 3 y ^{2}}

2 y^{^{''}} + 3 y^{^{'}} + y = t^{2} + 3 sin (t)

\int \frac{( 3 \cdot ln ( x ) - 5 ) ^{4}}{x} d x

y^{^{'}} = 7 e^{4 x - 5 y}, y (0) = 0

\frac{2}{( s ^{2} + 3 )}

\int_{- 5}^{- 2} 3 \frac{1}{x} d x

What is the derivative of y=ln(7x^2+3y^2) ?
The derivative of y=ln(7x^2+3y^2) is (14x)/(7x^2+3y^2)
What is the first derivative of y=ln(7x^2+3y^2) ?
The first derivative of y=ln(7x^2+3y^2) is (14x)/(7x^2+3y^2)