What is the integral of 9sin(x) ?

The integral of 9sin(x) is -9cos(x)+C

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integral of 9sin(x)

\int 9 sin (x) d x

- 9 cos (x) + C

Solution steps

\int 9 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 9 (- cos (x))

Simplify

= - 9 cos (x)

Add a constant to the solution

= - 9 cos (x) + C

\frac{d}{d x} (arcsinh (3 x))

\int x e^{9 x} d x

\int e^{\frac{z}{y}} d z

\frac{d}{d x} (\frac{3}{x ^{- 2}})

\frac{\partial}{\partial x} (1 + x^{2} y - x y)