What is (d^2)/(dx^2)(ln(x^2+1)) ?

The answer to (d^2)/(dx^2)(ln(x^2+1)) is (2(-x^2+1))/((x^2+1)^2)

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(d^2)/(dx^2)(ln(x^2+1))

\frac{d ^{2}}{d x ^{2}} (ln (x^{2} + 1))

\frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (ln (x^{2} + 1))

\frac{d}{d x} (ln (x^{2} + 1)) = \frac{2 x}{x ^{2} + 1}

= \frac{d}{d x} (\frac{2 x}{x ^{2} + 1})

\frac{d}{d x} (\frac{2 x}{x ^{2} + 1}) = \frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

= \frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

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What is (d^2)/(dx^2)(ln(x^2+1)) ?
The answer to (d^2)/(dx^2)(ln(x^2+1)) is (2(-x^2+1))/((x^2+1)^2)