What is the integral from 2 to 1 of x^2 ?

The integral from 2 to 1 of x^2 is -7/3

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integral from 2 to 1 of x^2

\int_{2}^{1} x^{2} d x

- \frac{7}{3}

Decimal Notation

- 2.33333 \dots

Solution steps

\int_{2}^{1} x^{2} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{2}

= - [\frac{x ^{3}}{3}]_{1}^{2}

Compute the boundaries:

\frac{7}{3}

= - \frac{7}{3}

x \to 1 + lim (\frac{1}{x})

\frac{d}{d x} (e^{5 - x})

f (x) = 22 x^{\frac{3}{2}} - 8 x^{\frac{1}{2}}

x \to 0 lim (+ (x + 4))

\frac{d}{d y} (y^{3} sin (6 x))

What is the integral from 2 to 1 of x^2 ?
The integral from 2 to 1 of x^2 is -7/3