en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=x^2+4

Solution

y^{^{'}} = x^{2} + 4

Solution

y = \frac{x ^{3}}{3} + 4 x + c_{1}

Solution steps

y^{'} (x) = x^{2} + 4

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x^{2} + 4 d x

\int x^{2} + 4 d x = \frac{x ^{3}}{3} + 4 x + c_{1}

y = \frac{x ^{3}}{3} + 4 x + c_{1}

Popular Examples

derivative of x/(1+(1.5574+6.09x^2^2))

\frac{d}{d x} (\frac{x}{1 + ( 1.5574 + 6.09 x ^{2} ) ^{2}})

(\partial)/(\partial x)(e^x+ycos(xy))

\frac{\partial}{\partial x} (e^{x} + y cos (x y))

integral of (-1/x)

\int (- \frac{1}{x}) d x

(\partial)/(\partial y)(x^2y+zcos(y))

\frac{\partial}{\partial y} (x^{2} y + z cos (y))

derivative of sin(-2ln(1-2x))

\frac{d}{d x} (sin (- 2 ln (1 - 2 x)))

Frequently Asked Questions (FAQ)

What is the solution for y^'=x^2+4 ?
The solution for y^'=x^2+4 is y=(x^3)/3+4x+c_{1}