What is the tangent of f(x)=10sqrt(x),(1,10) ?

The tangent of f(x)=10sqrt(x),(1,10) is y=5x+5

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tangent of f(x)=10sqrt(x),(1,10)

tangent of

f (x) = 10 x, (1, 10)

y = 5 x + 5

Solution steps

Find the slope of

f (x) = 10 x : \frac{df ( x )}{d x} = \frac{5}{x}

Compute the slope of

f (x) = 10 x

(1, 10) : m = 5

Find the line with slope m=

5

and passing through

(1, 10) : y = 5 x + 5

y = 5 x + 5

y = arccos (4 x^{2})

y = x^{2}, y = x + 2

\int (9 - x^{2})^{\frac{3}{2}} d x

\int \frac{1}{36 x ^{2} + 1} d x

(tan (θ))^{^{'}}

What is the tangent of f(x)=10sqrt(x),(1,10) ?
The tangent of f(x)=10sqrt(x),(1,10) is y=5x+5