en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x=y^3,x=y^2

Solution

area

x = y^{3}, x = y^{2}

Solution

\frac{1}{12}

+1

Decimal Notation

0.08333 \dots

Solution steps

Isolate

y

for

Isolate

y

for

x = y^{2} : y = x, y = - x

f_{2} (x) = x

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x = - x : x = 0

= \int_{0}^{1} ∣ f_{1} (x) - f_{2} (x) ∣ d x

= \frac{1}{12}

Popular Examples

integral of ((x+2))/(x^2+4x+5)

\int \frac{( x + 2 )}{x ^{2} + 4 x + 5} d x

derivative of-4xy

\frac{d}{d x} (- 4 x y)

integral of tan^3(x)sin(x)

\int tan^{3} (x) sin (x) d x

integral of (2x^3+5)x

\int (2 x^{3} + 5) x d x

limit as x approaches 1 of (x^2-2)/(x-1)

x \to 1 lim (\frac{x ^{2} - 2}{x - 1})

Frequently Asked Questions (FAQ)

What is area x=y^3,x=y^2 ?
The answer to area x=y^3,x=y^2 is 1/12