What is (\partial)/(\partial x)(x^2-y^2) ?

The answer to (\partial)/(\partial x)(x^2-y^2) is 2x

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(\partial)/(\partial x)(x^2-y^2)

\frac{\partial}{\partial x} (x^{2} - y^{2})

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 2 x - 0

Simplify

= 2 x

\frac{\partial}{\partial y} (ln (1 + x^{2} + y^{2}))

- sec (7 x) - ln (6 x)

x y^{^{'}} - y = x^{2017} y^{2}

e^{3 t} t^{2}

\int c^{3} t d t

What is (\partial)/(\partial x)(x^2-y^2) ?
The answer to (\partial)/(\partial x)(x^2-y^2) is 2x