What is the integral from 0 to 2 of (x^2-7x) ?

The integral from 0 to 2 of (x^2-7x) is -34/3

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integral from 0 to 2 of (x^2-7x)

\int_{0}^{2} (x^{2} - 7 x) d x

- \frac{34}{3}

Decimal Notation

- 11.33333 \dots

Solution steps

\int_{0}^{2} x^{2} - 7 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{2} d x - \int_{0}^{2} 7 x d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} 7 x d x = 14

= \frac{8}{3} - 14

Simplify

\frac{8}{3} - 14 : - \frac{34}{3}

= - \frac{34}{3}

\frac{d}{d x} (7 x + 2)

\frac{\partial}{\partial z} (z ln (x))

y^{^{''}} - 3 y^{^{'}} - 4 y = 0

n = 1 \sum \infty \frac{1}{n + 8}

\frac{d}{d x} ((x + 3) (2 x - 1)^{2})

What is the integral from 0 to 2 of (x^2-7x) ?
The integral from 0 to 2 of (x^2-7x) is -34/3