What is the tangent of f(x)=2x-5sqrt(x),(4,-2) ?

The tangent of f(x)=2x-5sqrt(x),(4,-2) is y= 3/4 x-5

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tangent of f(x)=2x-5sqrt(x),(4,-2)

tangent of

f (x) = 2 x - 5 x, (4, - 2)

y = \frac{3}{4} x - 5

Solution steps

Find the slope of

f (x) = 2 x - 5 x : \frac{df ( x )}{d x} = 2 - \frac{5}{2 x}

Compute the slope of

f (x) = 2 x - 5 x

(4, - 2) : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(4, - 2) : y = \frac{3}{4} x - 5

y = \frac{3}{4} x - 5

h \to 0 lim (3 x^{2} + 2 x h + h^{2})

\int 20 x ln (x) d x

\int (x^{3} e^{4 x}) d x

\int (x^{2} - 1)^{\frac{1}{2}} d x

n = 1 \sum \infty e^{- n^{2}}

What is the tangent of f(x)=2x-5sqrt(x),(4,-2) ?
The tangent of f(x)=2x-5sqrt(x),(4,-2) is y= 3/4 x-5