What is (\partial)/(\partial x)(e^{2xyz-3}) ?

The answer to (\partial)/(\partial x)(e^{2xyz-3}) is e^{2xyz-3}*2yz

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(\partial)/(\partial x)(e^{2xyz-3})

\frac{\partial}{\partial x} (e^{2 x yz - 3})

e^{2 x yz - 3} \cdot 2 yz

Solution steps

\frac{\partial}{\partial x} (e^{2 x yz - 3})

Treat

y, z

as constants

Apply the chain rule:

e^{2 x yz - 3} \frac{\partial}{\partial x} (2 x yz - 3)

= e^{2 x yz - 3} \frac{\partial}{\partial x} (2 x yz - 3)

\frac{\partial}{\partial x} (2 x yz - 3) = 2 yz

= e^{2 x yz - 3} \cdot 2 yz

y^{^{'}} = 9 y^{2}

\int \frac{2}{( x ^{2} + 2 ) ^{2}} d x

\frac{d y}{d x} = (y (x y^{3} - 1))

\int \frac{( cos ( x ) )}{x} d x

\int \frac{x}{( 9 - x ^{2} ) ^{2}} d x

What is (\partial)/(\partial x)(e^{2xyz-3}) ?
The answer to (\partial)/(\partial x)(e^{2xyz-3}) is e^{2xyz-3}*2yz