What is the integral from 0 to infinity of e^{-0.8x} ?

The integral from 0 to infinity of e^{-0.8x} is 1.25

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integral from 0 to infinity of e^{-0.8x}

\int_{0}^{\infty} e^{- 0.8 x} d x

1.25

Solution steps

\int_{0}^{\infty} e^{- 0.8 x} d x

Compute the indefinite integral:

\int e^{- 0.8 x} d x = - 1.25 e^{- 0.8 x} + C

Compute the boundaries:

\int_{0}^{\infty} e^{- 0.8 x} d x = 0 - (- 1.25)

= 0 - (- 1.25)

Simplify

= 1.25

y^{^{''}} + 8 y^{^{'}} + 32 y = 32, y (0) = 2, y^{^{'}} (0) = - 20

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\int_{0}^{\frac{3}{2} 3} \frac{x ^{3}}{9 - x ^{2}} d x

y = \frac{e ^{x} - e ^{- x}}{2}

\int x^{3} + 3 x - 2 d x

What is the integral from 0 to infinity of e^{-0.8x} ?
The integral from 0 to infinity of e^{-0.8x} is 1.25