What is the derivative of x+4/(x^2) ?

The derivative of x+4/(x^2) is 1-8/(x^3)

What is the first derivative of x+4/(x^2) ?

The first derivative of x+4/(x^2) is 1-8/(x^3)

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\frac{d}{d x} (x + \frac{4}{x ^{2}})

1 - \frac{8}{x ^{3}}

Solution steps

\frac{d}{d x} (x + \frac{4}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (\frac{4}{x ^{2}})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{4}{x ^{2}}) = - \frac{8}{x ^{3}}

= 1 - \frac{8}{x ^{3}}

\frac{d}{d x} (\frac{sin ( x ^{2} )}{x})

\frac{\partial}{\partial x} ((x + 2 y)^{2})

f (x) = ln (x^{3})

\int ∣ 2 x - 1 ∣ d x

\int \frac{1}{5 x ^{2} - 20 x + 100} d x

What is the derivative of x+4/(x^2) ?
The derivative of x+4/(x^2) is 1-8/(x^3)
What is the first derivative of x+4/(x^2) ?
The first derivative of x+4/(x^2) is 1-8/(x^3)