What is (\partial)/(\partial y)(e^{x-2}-y) ?

The answer to (\partial)/(\partial y)(e^{x-2}-y) is -1

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(\partial)/(\partial y)(e^{x-2}-y)

\frac{\partial}{\partial y} (e^{x - 2} - y)

- 1

Solution steps

\frac{\partial}{\partial y} (e^{x - 2} - y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{x - 2}) - \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (e^{x - 2}) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 - 1

Simplify

= - 1

\frac{d}{d x} (\frac{2 x}{4 + x})

\int \frac{1}{4 + t ^{2}} d t

\frac{\partial}{\partial x} (\frac{x - y}{x ^{2} + y ^{2} + 1})

f (x) = \frac{6 x + 14}{x + 7}

\int \frac{5}{sec ( x ) - 1} d x

What is (\partial)/(\partial y)(e^{x-2}-y) ?
The answer to (\partial)/(\partial y)(e^{x-2}-y) is -1