What is the derivative of 1/x+ln(x)+cot(2x) ?

The derivative of 1/x+ln(x)+cot(2x) is -1/(x^2)+1/x-csc^2(2x)*2

What is the first derivative of 1/x+ln(x)+cot(2x) ?

The first derivative of 1/x+ln(x)+cot(2x) is -1/(x^2)+1/x-csc^2(2x)*2

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derivative of

\frac{1}{x} + ln (x) + cot (2 x)

- \frac{1}{x ^{2}} + \frac{1}{x} - csc^{2} (2 x) \cdot 2

Solution steps

\frac{d}{d x} (\frac{1}{x} + ln (x) + cot (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x}) + \frac{d}{d x} (ln (x)) + \frac{d}{d x} (cot (2 x))

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d}{d x} (cot (2 x)) = - csc^{2} (2 x) \cdot 2

= - \frac{1}{x ^{2}} + \frac{1}{x} - csc^{2} (2 x) \cdot 2

y^{^{''}} - 4 y^{^{'}} + 4 y = 6 e^{2 x}

x \to 1 lim (x^{2} - 3 x + 2)

\int (8 x - 4) d x

x \to 1 lim (e^{3 x^{3} - 3 x})

\int_{0}^{0} x d x

What is the derivative of 1/x+ln(x)+cot(2x) ?
The derivative of 1/x+ln(x)+cot(2x) is -1/(x^2)+1/x-csc^2(2x)*2
What is the first derivative of 1/x+ln(x)+cot(2x) ?
The first derivative of 1/x+ln(x)+cot(2x) is -1/(x^2)+1/x-csc^2(2x)*2