What is the integral of sqrt(y-1) ?

The integral of sqrt(y-1) is 2/3 (y-1)^{3/2}+C

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integral of sqrt(y-1)

\int y - 1 d y

\frac{2}{3} (y - 1)^{\frac{3}{2}} + C

Solution steps

\int y - 1 d y

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = y - 1

= \frac{2}{3} (y - 1)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{3} (y - 1)^{\frac{3}{2}} + C

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What is the integral of sqrt(y-1) ?
The integral of sqrt(y-1) is 2/3 (y-1)^{3/2}+C